Homework

Weekly homework submissions:

Subsections of Homework

Week 1 HW: Principles and Practices

With a rather limited background in synthetic biology and bioengineering, I sketched out my initial scope of interest in closed-loop controllers…

1. Introduction

With a rather limited background in the field of synthetic biology and bioengineering, I sketched out my initial scope of interest in closed-loop controllers, in which they are autonomous and adjust to the environment around.

While I’m also interested in the bidirectional communication via the gut-brain axis. I want to explore the idea of engineering a gut bacterium with a synthetic genetic circuit that could detect biomarkers in the gut and conditionally produce neuroactive compounds that modulate brain activity via the GBA.

The circuit should ideally consist of a sensor module, processing module, and a response module. The logic is elucidated as following:

Inflammation detected → threshold exceeded → produce calming molecules → inflammation decreases → production shuts off.

This idea draws distinction from those open-loop, stress-relieving gummies and pills in that, this is a self-regulating therapeutic that produces compounds at the site where the gut-brain signaling infrastructure exists, and only produces upon conditional activation when the stress/inflammation biomarker exceeds a certain threshold.

2. Governance Goals

The overarching goal is Non-Malfeasance (preventing harm)

The nature of the technology involves releasing a genetically engineered organism into the human body, and potentially into the broader environment, making harm prevention and the Dual Use Research Concern (DUrC) indispensable presences and should be carried out at multiple scales.

SubGoal 1A: Preventing Uncontrolled Spread and Ecological Contamination

The engineered microbe must not exist beyond its therapeutic window, which means it should by no means spread to unintended hosts, or transfer its synthetic genes to wild microbial populations via the following possible routes:

  • Horizontal gene transfer (HGT): Synthetic circuit components (especially antibiotic resistance markers used in cloning) could transfer to pathogenic gut bacteria.
  • Environmental shedding: Engineered bacteria will be excreted and enter wastewater and soil ecosystems.
  • Mutation: The organism could evolve and mutate overtime to the point where the original means of control no longer works, or it can gain unintended functions.

SubGoal 1B: Preventing Negative Neurological/Immunological Effects

The closed-loop circuit must not overproduce compounds that trigger immune reactions within the body or interferes with the existing microbiome in unintended ways, such as:

  • Overproduction toxicity: A sensor that is too sensitive or a failed threshold filter could flood the gut with GABA/serotonin precursors.
  • Immune overactivation: The engineered organism might trigger inflammatory responses, paradoxically worsening the target condition.
  • Microbiome disruption: The engineered organism at therapeutic densities could outcompete native beneficial bacteria.

Governance must address who gets access and whether patients can meaningfully consent to hosting a living engineered organism, as the commitment is larger than taking in a single pill.

3. Potential Actions

Three potential governance actions are considered below, incorporating 1) Purpose, 2) Design, 3) Assumptions, and 4) Risk of Failure and “Success”.

Governance Action 1: Comprehensive policy framework and clear assignment on roles played by different actors

Purpose: The work conducted with living organisms in making them biotherapeutic product usually fall under FDA’s established framework of CBER, but due to the closed-loop nature of the synthetic circuit, there are no detailed requirements/regulations revolving around how to exert controllable influence that distinguishes from the treatment of those open-looped projects.

Design: Given the participation of various actors, when FDA issues the guidance, academic labs should design/provide corresponding biocontainment tools. While biotech companies comply and absorb testing costs. Research agencies should then standardize biocontainment toolkits to lower barriers for smaller labs. Cross-agency coordination with environmental protection agencies (e.g. EPA) may be needed.

Assumptions

  • Effective switches can be engineered over time to keep the microbiome in check
  • FDA has sufficient synbio experts in evaluating the circuit design
  • In vitro stability testing predicts in vivo behavior

Risks

  • Failure: IF the standards were set too high making the project difficult to perform, it could lead to the decline in industry as small labs and startups may choose to opt out.
  • Success: A standard designed too well could lead to underestimation of risks.

Governance Action 2: Long Term Monitoring and Clinical Trials

Purpose: Given the closed-loop nature and the potential changes that could occur in living therapeutics, clincal trial framework should establish different tiers that occurs over a designated timescale for constant surveillance.

Design: The clinical trials should develop at least three tiers, with

  • Tier 1 (1-3 yr): Standard testing phase
  • Tier 2 (5 yr): Mandatory microbiome monitoring and tracking of genomic sequences
  • Tier 3: Constant survillance of wastewater disposal in experimenting/trial regions

Assumptions

  • Patient will remain in 5 year follow up
  • The engineered organism can be effectively tracked within gut environment

Risks

  • Failure: Unforseen development of organism is sighted after widespread distribution.
  • Success: Over institutionalized framework could slow development of future iterations.

Governance Action 3: Transparency and International Oversee

Purpose: In considering the potential widespread use of such ideation, the public should gain transparency to the fundamental logic/codes. Simultaneously, international harmonization groups like WHO should develop and align the set of harmonized minimum standards for testing and monitoring.

Design: National governments in coordinating and aligning regulations under international organizations and synbio industry leaders. Commited collaboration between public and private sectors in a foreseeable timescale.

Assumptions

  • Committed support among decision maker exists despite current issue in international relations.
  • Applicable universal standard despite different cultural practice
  • Development of technology be in pace with international harmonization.

Risks

  • Failure: No actual efforts of enforcement made.
  • Success: Rigorous standards that further stabilize the advantage of developed countries, and enlarge the medical development and accessibilities between countries.

4. Scoring Framework

The following rubric evaluates the governance options presented above on a 1–3 scale (1=week/limited, 2=moderate, 3=strong) across the span of biosecurity, lab safety, environmental protection, and practical considerations.
Does the option:Option 1Option 2Option 3
Enhance Biosecurity
• By preventing incidents322
• By helping respond133
Foster Lab Safety
• By preventing incident322
• By helping respond221
Protect the environment
• By preventing incidents322
• By helping respond133
Other considerations
• Minimizing costs and burdens to stakeholders221
• Feasibility?231
• Not impede research122
• Promote constructive applications233
Total202420

5. Prioritized Option

Given the overall scoring, Governance Action 2 yields the highest total amongst the three, because the design in stages of trial over a timescale monitors the progress of experiment closely and allows for early detection of incidents. The gradual development also allows brings the market into consideration, making the idea of wide application possible.

However, it also contain weakness that needs to be accompanied by complementary actions. Specifically on prevention, Action 1 scores higher in that it implants kill switches in the initial engineering phase.

Action 3 touches a little bit of everything, but it should be of a later consideration when the technology and domestic standards became more mature, as implementing regulations on an international level generates huge costs and often require longer time for reconciliation/negotiation.


Assignment:

Questions from Professor Jacobson

Nature’s machinery for copying DNA is called polymerase. What is the error rate of polymerase? How does this compare to the length of the human genome. How does biology deal with that discrepancy?

The error rate, according to slide 8, is 1:10^6. The human genome as noted is 3.2 billion base pairs (gbp), and hence if we were to do the calculation there would be around three thousand new mutations/cell division. The biology deals with the discrepancy through error correction like MutS Repair System, that detects the mismatched base pairs and resynthesize it correctly, therefore bringing down the error rate and enabling the copying to proceed with very few/zero errors.

How many different ways are there to code (DNA nucleotide code) for an average human protein? In practice what are some of the reasons that all of these different codes don’t work to code for the protein of interest?

An average human protein is encoded by around 1036 base pairs of DNA (slide 6), and divided by three (codon) will get roughly around 345 amino acids/protein. So given the number, there’s around 10^150 possible DNA sequences that result in the same primary chain of amino acids. But the majority are redundant, and in some situations a sequence of amino acid would create mRNA structures like hairpin that blocks the ribosome from binding and the forming of right protein.


Questions from Professor LeProust

What’s the most commonly used method for oligo synthesis currently?

The most used method is the phosphoramidite method, which is a 4 step chemical cycle that repeats for N times, specifically including coupling (with phosphoramidite), capping (unreacted sites), oxidation, and deblocking.

Why is it difficult to make oligos longer than 200nt via direct synthesis?

It is difficult mainly due to the inefficiency of the coupling steps and the accumulation of errors, given the exponentially decaying yield, as the error rate accumlates, the majority would be of failure sequence by the time it reaches 200.

Why can’t you make a 2000bp gene via direct oligo synthesis?

Because the direct oligo synthesis is performed via phosphoramidite, and due to the multiplicative nature of the success rate and the final yield follows an exponential decay curve, as the number of nucleotides increases, the accuracy will go down. By the time it reaches 2000, it would be hardly possible to extract the correct sequence among all disturbances and noises. Hence bioengineers synthesize smaller oligos and stitch them together to ensure the correct sequence.


Question from Professor Church

What are the 10 essential amino acids in all animals and how does this affect your view of the “Lysine Contingency”?

The 10 essential amino acid (from the slide and with the aid of google) are listed below:

  • Arginine (Arg)
  • Histidine (His)
  • Isoleucine (Ile)
  • Leucine (Leu)
  • Lysine (Lys)
  • Methionine (Met)
  • Phenylalanine (Phe)
  • Threonine (Thr)
  • Tryptophan (Trp)
  • Valine (Val)

The Lysine Contingency (according to Google) refers to the genetic alteration performed in the movie Jurassic Park, that made dinosaurs unable to produce lysine, therefore relying on human supplements to survive. But this idea does not stand as it is an essential amino acid within them that doesn’t need to be synthesized, and hence dinosaurs can gain lysine by eating other organisms. This idea sheds light on the biocontainment method of NSAA (non standard amino acid), which organisms cannot obtain in a natural setting, and hence is a more secure contingency.


Week 2 HW: DNA Read, Write, and Edit

3.1. Choose your protein.

In recitation, we discussed that you will pick a protein for your homework that you find interesting. Which protein have you chosen and why? Using one of the tools described in recitation (NCBI, UniProt, google), obtain the protein sequence for the protein you chose.

I have selected PIEZO1 as my protein, that is a protein sitting in the cell membrane and opens when the membrane is physically stretched, compressed, or deformed, basically detecting the membrane tension.

Protein Sequence (2,521 aa)

Click to expand full protein sequence
>PIEZO1_Homo_sapiens | 2521 aa | Mechanosensitive ion channel
MEPHVLGAVLYWLLLPCALLAACLLRFSGLSLVYLLFLLLLPWFPGPTRCGLQGHTGRLL
RALLGLSLLFLVAHLALQICLHIVPRLDQLLGPSCSRWETLSRHIGVTRLDLKDIPNAIR
LVAPDLGILVVSSVCLGICGRLARNTRQSPHPRELDDDERDVDASPTAGLQEAATLAPTR
RSRLAARFRVTAHWLLVAAGRVLAVTLLALAGIAHPSALSSVYLLLFLALCTWWACHFPIS
TRGFSRLCVAVGCFGAGHLICLYCYQMPLAQALLPPAGIWARVLGLKDFVGPTNCSSPHA
LVLNTGLDWPVYASPGVLLLLCYATASLRKLRAYRPSGQRKEAAKGYEARELELAELDQW
PQERESDQHVVPTAPDTEADNCIVHELTGQSSVLRRPVRPKRAEPREASPLHSLGHLIM
DQSYVCALIAMMVWSITYHSWLTFVLLLWACLIWTVRSRHQLAMLCSPCILLYGMTLCCL
RYVWAMDLRPELPTTLGPVSLRQLGLEHTRYPCLDLGAMLLYTLTFWLLLRQFVKEKLLK
WAESPAALTEVTVADTEPTRTQTLLQSLGELVKGVYAKYWIYVCAGMFIVVSFAGRLVVY
KIVYMFLFLLCLTLFQVYYSLWRKLLKAFWWLVVAYTMLVLIAVYTFQFQDFPAYWRNLT
GFTDEQLGDLGLEQFSVSELFSSILVPGFFLLACILQLHYFHRPFMQLTDMEHVSLPGTR
LPRWAHRQDAVSGTPLLREEQQEHQQQQQEEEEEEEDSRDEGLGVATPHQATQVPEGAAK
WGLVAERLLELAAGFSDVLSRVQVFLRRLLELHVFKLVALYTVWVALKEVSVMNLLLVVL
WAFALPYPRFRPMASCLSTVWTCVIIVCKMLYQLKVVNPQEYSSNCTEPFPNSTNLLPTE
ISQSLLYRGPVDPANWFGVRKGFPNLGYIQNHLQVLLLLVFEAIVYRRQEHYRRQHQLA
PLPAQAVFASGTRQQLDQDLLGCLKYFINFFFYKFGLEICFLMAVNVIGQRMNFLVTLHG
CWLVAILTRRHRQAIARLWPNYCLFLALFLLYQYLLCLGMPPALCIDYPWRWSRAVPMNS
ALIKWLYLPDFFRAPNSTNLISDFLLLLCASQQWQVFSAERTEEWQRMAGVNTDRLEPLR
GEPNPVPNFIHCRSYLDMLKVAVFRYLFWLVLVVVFVTGATRISIFGLGYLLACFYLLLF
GTALLQRDTRARLVLWDCLILYNVTVIISKNMLSLLACVFVEQMQTGFCWVIQLFSLVCT
VKGYYDPKEMMDRDQDCLLPVEEAGIIWDSVCFFFLLLQRRVFLSHYYLHVRADLQATAL
LASRGFALYNAANLKSIDFHRRIEEKSLAQLKRQMERIRAKQEKHRQGRVDRSRPQDTLG
PKDPGLEPGPDSPGGSSPPRRQWWRPWLDHATVIHSGDYFLFESDSEEEEEAVPEDPRPS
AQSAFQLAYQAWVTNAQAVLRRRQQEQEQARQEQAGQLPTGGGPSQEVEPAEGPEEAAA
GRSHVVQRVLSTAQFLWMLGQALVDELTRWLQEFTRHHGTMSDVLRAERYLLTQELLQGG
EVHRGVLDQLYTSQAEATLPGPTEAPNAPSTVSSGLGAEEPLSSMTDDMGSPLSTGYHTR
SGSEEAVTDPGEREAGASLYQGLMRTASELLLDRRLRIPELEEAELFAEGQGRALRLLRAV
YQCVAAHSELLCYFIIILNHMVTASAGSLVLPVLVFLWAMLSIPRPSKRFWMTAIVFTE
IAVVVKYLFQFGFFPWNSHVVLRRYENKPYFPPRILGLEKTDGYIKYDLVQLMALFFHRS
QLLCYGLWDHEEDSPSKEHDKSGEEEQGAEEGPGVPAATTEDHIQVEARVGPTDGTPEPQ
VELRPRDTRRISLRFRRRKKEGPARKGAAAIEAEDREEEEGEEEKEAPTGREKRPSRSGGR
VRAAGRRLQGFCLSLAQGTYRPLRRFFHDILHTKYRAATDVYALMFLADVVDFIIIIFGFW
AFGKHSAATDITSSLSDDQVPEAFLVMLLIQFSTMVVDRALYLRKTVLGKLAFQVALVLA
IHLWMFFILPAVTERMFNQNVVAQLWYFVKCIYFALSAYQIRCGYPTRILGNFLTKKYNHL
NLFLFQGFRLVPFLVELRAVMDWVWTDTTLSLSSWMCVEDIYANIFIIKCSRETEKKYPQP
KGQKKKKIVKYGMGGLIILFLIAIIWFPLLFMSLVRSVVGVVNQPIDVTVTLKLGGYEPL
FTMSAQQPSIIPFTAQAYEELSRQFDPQPLAMQFISQYSPEDIVTAQIEGSSGALWRISPP
SRAQMKRELYNGTADITLRFTWNFQRDLAKGGTVEYANEKHMLALAPNSTARRQLASLLE
GTSDQSVVIPNLFPKYIRAPNGPEANPVKQLQPNEEADYLGVRIQLRREQGAGATGFLEW
WVIELQECRTDCNLLPMVIFSDKVSPPSLGFLAGYGIMGLYVSIVLVIGKFVRGFFSEIS
HSIMFEELPCVDRILKLCQDIFLVRETRELELEEELYAKLIFLYRSPETMIKWTREKE

Key features: 38 transmembrane helices/monomer · Trimeric propeller architecture · ~900 kDa functional complex


3.2. Reverse Translate: Protein (amino acid) sequence to DNA (nucleotide) sequence.

The Central Dogma discussed in class and recitation describes the process in which DNA sequence becomes transcribed and translated into protein. The Central Dogma gives us the framework to work backwards from a given protein sequence and infer the DNA sequence that the protein is derived from. Using one of the tools discussed in class, NCBI or online tools (google “reverse translation tools”), determine the nucleotide sequence that corresponds to the protein sequence you chose above.

Native DNA Sequence (7,566 bp)

Click to expand native DNA coding sequence
>PIEZO1_CDS_native | 7566 bp | Homo sapiens
atggaaccgcatgtgctgggcgcggtgctgtattggctgctgctgccgtgcgcgctgctg
gcggcgtgcctgctgcgctttagcggcctgagcctggtgtatctgctgtttctgctgctg
ctgccgtggtttccgggcccgacccgctgcggcctgcagggccataccggccgcctgctg
cgcgcgctgctgggcctgagcctgctgtttctggtggcgcatctggcgctgcagatttgc
ctgcatattgtgccgcgcctggatcagctgctgggcccgagctgcagccgctgggaaacc
ctgagccgccatattggcgtgacccgcctggatctgaaagatattccgaacgcgattcgc
ctggtggcgccggatctgggcattctggtggtgagcagcgtgtgcctgggcatttgcggc
cgcctggcgcgcaacacccgccagagcccgcatccgcgcgaactggatgatgatgaacgc
gatgtggatgcgagcccgaccgcgggcctgcaggaagcggcgaccctggcgccgacccgc
cgcagccgcctggcggcgcgctttcgcgtgaccgcgcattggctgctggtggcggcgggc
cgcgtgctggcggtgaccctgctggcgctggcgggcattgcgcatccgagcgcgctgagc
agcgtgtatctgctgctgtttctggcgctgtgcacctggtgggcgtgccattttccgatt
agcacccgcggctttagccgcctgtgcgtggcggtgggctgctttggcgcgggccatctg
atttgcctgtattgctatcagatgccgctggcgcaggcgctgctgccgccggcgggcatt
tgggcgcgcgtgctgggcctgaaagattttgtgggcccgaccaactgcagcagcccgcat
gcgctggtgctgaacaccggcctggattggccggtgtatgcgagcccgggcgtgctgctg
ctgctgtgctatgcgaccgcgagcctgcgcaaactgcgcgcgtatcgcccgagcggccag
cgcaaagaagcggcgaaaggctatgaagcgcgcgaactggaactggcggaactggatcag
tggccgcaggaacgcgaaagcgatcagcatgtggtgccgaccgcgccggataccgaagcg
gataactgcattgtgcatgaactgaccggccagagcagcgtgctgcgccgcccggtgcgc
ccgaaacgcgcggaaccgcgcgaagcgagcccgctgcatagcctgggccatctgattatg
gatcagagctatgtgtgcgcgctgattgcgatgatggtgtggagcattacctatcatagc
tggctgacctttgtgctgctgctgtgggcgtgcctgatttggaccgtgcgcagccgccat
cagctggcgatgctgtgcagcccgtgcattctgctgtatggcatgaccctgtgctgcctg
cgctatgtgtgggcgatggatctgcgcccggaactgccgaccaccctgggcccggtgagc
ctgcgccagctgggcctggaacatacccgctatccgtgcctggatctgggcgcgatgctg
ctgtataccctgaccttttggctgctgctgcgccagtttgtgaaagaaaaactgctgaaa
tgggcggaaagcccggcggcgctgaccgaagtgaccgtggcggataccgaaccgacccgc
acccagaccctgctgcagagcctgggcgaactggtgaaaggcgtgtatgcgaaatattgg
atttatgtgtgcgcgggcatgtttattgtggtgagctttgcgggccgcctggtggtgtat
aaaattgtgtatatgtttctgtttctgctgtgcctgaccctgtttcaggtgtattatagc
ctgtggcgcaaactgctgaaagcgttttggtggctggtggtggcgtataccatgctggtg
ctgattgcggtgtatacctttcagtttcaggattttccggcgtattggcgcaacctgacc
ggctttaccgatgaacagctgggcgatctgggcctggaacagtttagcgtgagcgaactg
tttagcagcattctggtgccgggcttttttctgctggcgtgcattctgcagctgcattat
tttcatcgcccgtttatgcagctgaccgatatggaacatgtgagcctgccgggcacccgc
ctgccgcgctgggcgcatcgccaggatgcggtgagcggcaccccgctgctgcgcgaagaa
cagcaggaacatcagcagcagcagcaggaagaagaagaagaagaagaagatagccgcgat
gaaggcctgggcgtggcgaccccgcatcaggcgacccaggtgccggaaggcgcggcgaaa
tggggcctggtggcggaacgcctgctggaactggcggcgggctttagcgatgtgctgagc
cgcgtgcaggtgtttctgcgccgcctgctggaactgcatgtgtttaaactggtggcgctg
tataccgtgtgggtggcgctgaaagaagtgagcgtgatgaacctgctgctggtggtgctg
tgggcgtttgcgctgccgtatccgcgctttcgcccgatggcgagctgcctgagcaccgtg
tggacctgcgtgattattgtgtgcaaaatgctgtatcagctgaaagtggtgaacccgcag
gaatatagcagcaactgcaccgaaccgtttccgaacagcaccaacctgctgccgaccgaa
attagccagagcctgctgtatcgcggcccggtggatccggcgaactggtttggcgtgcgc
aaaggctttccgaacctgggctatattcagaaccatctgcaggtgctgctgctgctggtg
tttgaagcgattgtgtatcgccgccaggaacattatcgccgccagcatcagctggcgccg
ctgccggcgcaggcggtgtttgcgagcggcacccgccagcagctggatcaggatctgctg
ggctgcctgaaatattttattaacttttttttttataaatttggcctggaaatttgcttt
ctgatggcggtgaacgtgattggccagcgcatgaactttctggtgaccctgcatggctgc
tggctggtggcgattctgacccgccgccatcgccaggcgattgcgcgcctgtggccgaac
tattgcctgtttctggcgctgtttctgctgtatcagtatctgctgtgcctgggcatgccg
ccggcgctgtgcattgattatccgtggcgctggagccgcgcggtgccgatgaacagcgcg
ctgattaaatggctgtatctgccggatttttttcgcgcgccgaacagcaccaacctgatt
agcgattttctgctgctgctgtgcgcgagccagcagtggcaggtgtttagcgcggaacgc
accgaagaatggcagcgcatggcgggcgtgaacaccgatcgcctggaaccgctgcgcggc
gaaccgaacccggtgccgaactttattcattgccgcagctatctggatatgctgaaagtg
gcggtgtttcgctatctgttttggctggtgctggtggtggtgtttgtgaccggcgcgacc
cgcattagcatttttggcctgggctatctgctggcgtgcttttatctgctgctgtttggc
accgcgctgctgcagcgcgatacccgcgcgcgcctggtgctgtgggattgcctgattctg
tataacgtgaccgtgattattagcaaaaacatgctgagcctgctggcgtgcgtgtttgtg
gaacagatgcagaccggcttttgctgggtgattcagctgtttagcctggtgtgcaccgtg
aaaggctattatgatccgaaagaaatgatggatcgcgatcaggattgcctgctgccggtg
gaagaagcgggcattatttgggatagcgtgtgctttttttttctgctgctgcagcgccgc
gtgtttctgagccattattatctgcatgtgcgcgcggatctgcaggcgaccgcgctgctg
gcgagccgcggctttgcgctgtataacgcggcgaacctgaaaagcattgattttcatcgc
cgcattgaagaaaaaagcctggcgcagctgaaacgccagatggaacgcattcgcgcgaaa
caggaaaaacatcgccagggccgcgtggatcgcagccgcccgcaggataccctgggcccg
aaagatccgggcctggaaccgggcccggatagcccgggcggcagcagcccgccgcgccgc
cagtggtggcgcccgtggctggatcatgcgaccgtgattcatagcggcgattattttctg
tttgaaagcgatagcgaagaagaagaagaagcggtgccggaagatccgcgcccgagcgcg
cagagcgcgtttcagctggcgtatcaggcgtgggtgaccaacgcgcaggcggtgctgcgc
cgccgccagcaggaacaggaacaggcgcgccaggaacaggcgggccagctgccgaccggc
ggcggcccgagccaggaagtggaaccggcggaaggcccggaagaagcggcggcgggccgc
agccatgtggtgcagcgcgtgctgagcaccgcgcagtttctgtggatgctgggccaggcg
ctggtggatgaactgacccgctggctgcaggaatttacccgccatcatggcaccatgagc
gatgtgctgcgcgcggaacgctatctgctgacccaggaactgctgcagggcggcgaagtg
catcgcggcgtgctggatcagctgtataccagccaggcggaagcgaccctgccgggcccg
accgaagcgccgaacgcgccgagcaccgtgagcagcggcctgggcgcggaagaaccgctg
agcagcatgaccgatgatatgggcagcccgctgagcaccggctatcatacccgcagcggc
agcgaagaagcggtgaccgatccgggcgaacgcgaagcgggcgcgagcctgtatcagggc
ctgatgcgcaccgcgagcgaactgctgctggatcgccgcctgcgcattccggaactggaa
gaagcggaactgtttgcggaaggccagggccgcgcgctgcgcctgctgcgcgcggtgtat
cagtgcgtggcggcgcatagcgaactgctgtgctattttattattattctgaaccatatg
gtgaccgcgagcgcgggcagcctggtgctgccggtgctggtgtttctgtgggcgatgctg
agcattccgcgcccgagcaaacgcttttggatgaccgcgattgtgtttaccgaaattgcg
gtggtggtgaaatatctgtttcagtttggcttttttccgtggaacagccatgtggtgctg
cgccgctatgaaaacaaaccgtattttccgccgcgcattctgggcctggaaaaaaccgat
ggctatattaaatatgatctggtgcagctgatggcgctgttttttcatcgcagccagctg
ctgtgctatggcctgtgggatcatgaagaagatagcccgagcaaagaacatgataaaagc
ggcgaagaagaacagggcgcggaagaaggcccgggcgtgccggcggcgaccaccgaagat
catattcaggtggaagcgcgcgtgggcccgaccgatggcaccccggaaccgcaggtggaa
ctgcgcccgcgcgatacccgccgcattagcctgcgctttcgccgccgcaaaaaagaaggc
ccggcgcgcaaaggcgcggcggcgattgaagcggaagatcgcgaagaagaagaaggcgaa
gaagaaaaagaagcgccgaccggccgcgaaaaacgcccgagccgcagcggcggccgcgtg
cgcgcggcgggccgccgcctgcagggcttttgcctgagcctggcgcagggcacctatcgc
ccgctgcgccgcttttttcatgatattctgcataccaaatatcgcgcggcgaccgatgtg
tatgcgctgatgtttctggcggatgtggtggattttattattattatttttggcttttgg
gcgtttggcaaacatagcgcggcgaccgatattaccagcagcctgagcgatgatcaggtg
ccggaagcgtttctggtgatgctgctgattcagtttagcaccatggtggtggatcgcgcg
ctgtatctgcgcaaaaccgtgctgggcaaactggcgtttcaggtggcgctggtgctggcg
attcatctgtggatgttttttattctgccggcggtgaccgaacgcatgtttaaccagaac
gtggtggcgcagctgtggtattttgtgaaatgcatttattttgcgctgagcgcgtatcag
attcgctgcggctatccgacccgcattctgggcaactttctgaccaaaaaatataaccat
ctgaacctgtttctgtttcagggctttcgcctggtgccgtttctggtggaactgcgcgcg
gtgatggattgggtgtggaccgataccaccctgagcctgagcagctggatgtgcgtggaa
gatatttatgcgaacatttttattattaaatgcagccgcgaaaccgaaaaaaaatatccg
cagccgaaaggccagaaaaaaaaaaaaattgtgaaatatggcatgggcggcctgattatt
ctgtttctgattgcgattatttggtttccgctgctgtttatgagcctggtgcgcagcgtg
gtgggcgtggtgaaccagccgattgatgtgaccgtgaccctgaaactgggcggctatgaa
ccgctgtttaccatgagcgcgcagcagccgagcattattccgtttaccgcgcaggcgtat
gaagaactgagccgccagtttgatccgcagccgctggcgatgcagtttattagccagtat
agcccggaagatattgtgaccgcgcagattgaaggcagcagcggcgcgctgtggcgcatt
agcccgccgagccgcgcgcagatgaaacgcgaactgtataacggcaccgcggatattacc
ctgcgctttacctggaactttcagcgcgatctggcgaaaggcggcaccgtggaatatgcg
aacgaaaaacatatgctggcgctggcgccgaacagcaccgcgcgccgccagctggcgagc
ctgctggaaggcaccagcgatcagagcgtggtgattccgaacctgtttccgaaatatatt
cgcgcgccgaacggcccggaagcgaacccggtgaaacagctgcagccgaacgaagaagcg
gattatctgggcgtgcgcattcagctgcgccgcgaacagggcgcgggcgcgaccggcttt
ctggaatggtgggtgattgaactgcaggaatgccgcaccgattgcaacctgctgccgatg
gtgatttttagcgataaagtgagcccgccgagcctgggctttctggcgggctatggcatt
atgggcctgtatgtgagcattgtgctggtgattggcaaatttgtgcgcggcttttttagc
gaaattagccatagcattatgtttgaagaactgccgtgcgtggatcgcattctgaaactg
tgccaggatatttttctggtgcgcgaaacccgcgaactggaactggaagaagaactgtat
gcgaaactgatttttctgtatcgcagcccggaaaccatgattaaatggacccgcgaaaaa
gaa

3.3. Codon optimization.

Once a nucleotide sequence of your protein is determined, you need to codon optimize your sequence. You may, once again, utilize google for a “codon optimization tool”. In your own words, describe why you need to optimize codon usage. Which organism have you chosen to optimize the codon sequence for and why?

  1. E. coli Codon-Optimized DNA (7,566 bp)

Optimized for expression in E. coli C43(DE3). Rare codons (AGG/AGA for Arg, CUA for Leu, AUA for Ile) replaced with E. coli-preferred synonymous codons to prevent ribosomal stalling and improve yield.

Click to expand E. coli-optimized sequence (codon-spaced)
>PIEZO1_Ecoli_optimized | 7566 bp | Codons spaced for readability
ATG GAA CCG CAT GTT TTG GGG GCG GTG CTC TAT TGG CTG CTC TTA CCG TGC
GCG TTA TTG GCC GCT TGT CTT CTG CGC TTT AGC GGC CTG TCT CTC GTG TAC
CTG CTT TTT CTG CTG CTG CTT CCG TGG TTC CCG GGC CCT ACG CGT TGT GGT
TTG CAA GGT CAT ACG GGT CGC TTA TTG CGC GCG CTG CTT GGC CTG TCC TTA
TTA TTT CTT GTG GCC CAT TTA GCC CTG CAA ATT TGT CTG CAT ATC GTT CCG
CGC CTG GAT CAG TTG CTG GGC CCG TCC TGC TCA CGC TGG GAG ACA TTG AGC
CGC CAT ATT GGG GTC ACG CGT TTA GAT CTC AAA GAT ATT CCT AAC GCT ATC
CGT TTG GTG GCG CCA GAC TTA GGT ATT CTG GTG GTG TCG AGC GTT TGT CTG
GGT ATT TGC GGT CGT CTG GCA CGT AAC ACG CGG CAG TCA CCT CAT CCG CGT
GAG CTC GAT GAT GAT GAG CGC GAT GTG GAT GCG AGT CCT ACC GCC GGC CTC
CAG GAG GCT GCG ACG CTC GCC CCG ACA CGC CGC TCG CGC CTG GCC GCA CGC
TTT CGC GTT ACG GCC CAT TGG CTG CTC GTA GCA GCA GGT CGT GTC CTG GCA
GTG ACG CTC CTG GCC CTT GCC GGG ATT GCG CAC CCG TCA GCG CTG AGC AGC
GTG TAC CTG TTA CTG TTC CTG GCG CTT TGC ACC TGG TGG GCC TGC CAT TTT
CCG ATC AGC ACA CGT GGC TTC TCC CGC CTG TGC GTG GCT GTA GGC TGT TTT
GGC GCA GGG CAT CTT ATT TGT CTT TAT TGC TAT CAG ATG CCT CTG GCT CAG
GCT TTG CTG CCG CCA GCA GGC ATC TGG GCC CGC GTG CTG GGT CTT AAA GAC
TTT GTT GGT CCG ACC AAC TGC TCA AGC CCT CAT GCC CTG GTG TTA AAT ACC
GGT TTA GAT TGG CCG GTG TAT GCA AGT CCG GGT GTT CTC CTG CTC CTT TGT
TAC GCC ACC GCA TCC TTG CGC AAA CTC CGC GCC TAT CGT CCG TCC GGG CAG
CGT AAA GAA GCG GCG AAA GGC TAC GAA GCA CGC GAA TTA GAA TTG GCT GAG
CTG GAT CAA TGG CCG CAG GAA CGT GAG AGC GAT CAG CAC GTT GTG CCG ACA
GCG CCG GAT ACC GAA GCG GAT AAC TGT ATC GTA CAC GAA CTG ACT GGT CAG
TCC AGT GTG TTA CGT CGC CCG GTT CGC CCG AAG CGG GCA GAA CCG CGG GAA
GCT TCC CCG CTC CAT AGC TTG GGC CAT CTG ATC ATG GAT CAG TCT TAT GTA
TGC GCA CTG ATC GCG ATG ATG GTA TGG TCT ATC ACC TAC CAC TCT TGG CTT
ACT TTT GTG CTT TTG CTG TGG GCC TGT CTG ATC TGG ACC GTT CGC TCG CGC
CAT CAG TTA GCC ATG CTG TGC TCA CCG TGC ATC CTT CTG TAT GGC ATG ACC
TTA TGC TGC CTT CGC TAT GTA TGG GCG ATG GAT CTT CGT CCG GAG CTC CCA
ACG ACG CTG GGC CCG GTG AGT CTG CGC CAG TTG GGT TTA GAA CAC ACG CGC
TAC CCG TGC CTG GAT TTG GGG GCG ATG CTG TTG TAT ACG CTG ACA TTT TGG
TTA TTG TTG CGG CAG TTC GTT AAG GAG AAA CTG CTC AAA TGG GCG GAA TCT
CCG GCA GCC TTG ACC GAG GTG ACC GTC GCG GAT ACA GAG CCG ACG CGT ACA
CAG ACC CTG CTG CAG TCG TTG GGC GAA TTG GTG AAA GGG GTG TAT GCC AAG
TAC TGG ATC TAT GTT TGT GCG GGT ATG TTT ATC GTA GTG TCC TTC GCC GGG
CGT CTG GTG GTG TAT AAA ATT GTT TAT ATG TTT CTG TTC CTG CTT TGC CTG
ACT TTA TTC CAG GTC TAC TAT TCA CTT TGG CGT AAA TTG CTC AAG GCC TTT
TGG TGG CTT GTC GTT GCG TAT ACC ATG TTG GTC CTG ATC GCC GTG TAT ACC
TTT CAG TTT CAG GAT TTC CCG GCC TAT TGG CGT AAT CTG ACC GGT TTC ACC
GAT GAA CAG CTG GGT GAC CTG GGT CTG GAG CAA TTT TCC GTT AGC GAA CTG
TTC AGC AGT ATC CTC GTG CCG GGT TTT TTT TTA CTC GCG TGT ATT CTG CAG
CTC CAT TAC TTT CAT CGT CCG TTC ATG CAA TTA ACA GAC ATG GAA CAT GTA
AGC TTG CCG GGT ACG CGC CTG CCT CGC TGG GCC CAC CGG CAG GAT GCC GTC
TCA GGC ACA CCG TTG CTG CGT GAA GAA CAG CAG GAA CAC CAG CAG CAG CAA
CAA GAG GAG GAA GAA GAA GAA GAA GAT TCT CGC GAT GAA GGC CTT GGT GTC
GCC ACC CCT CAC CAG GCA ACC CAA GTC CCG GAG GGG GCC GCC AAA TGG GGT
CTG GTT GCC GAG CGG TTG CTT GAA TTG GCA GCA GGC TTT AGT GAC GTG CTC
TCG CGT GTC CAA GTT TTT CTT CGT CGT CTG TTA GAA CTG CAC GTG TTT AAG
TTA GTA GCG TTA TAT ACG GTA TGG GTC GCG TTG AAA GAG GTC TCT GTT ATG
AAT CTG CTG TTG GTT GTG TTG TGG GCG TTT GCG CTG CCG TAT CCA CGC TTT
CGG CCG ATG GCG TCA TGT CTT TCG ACA GTG TGG ACC TGT GTT ATC ATC GTG
TGT AAA ATG CTG TAT CAG TTG AAA GTG GTT AAT CCG CAA GAG TAT AGT TCC
AAC TGT ACG GAA CCG TTT CCG AAC TCG ACC AAT CTG CTC CCG ACC GAG ATC
TCT CAG TCT CTC CTG TAT CGT GGG CCA GTG GAC CCG GCG AAC TGG TTT GGT
GTG CGC AAA GGC TTT CCG AAT TTG GGC TAC ATT CAG AAC CAC CTG CAA GTC
CTC CTG CTG CTG GTG TTT GAA GCG ATT GTG TAT CGC CGT CAA GAA CAT TAT
CGT CGT CAA CAT CAG TTG GCG CCT CTG CCT GCG CAG GCT GTT TTC GCA TCC
GGT ACG CGT CAA CAA CTG GAT CAG GAC CTG CTG GGT TGC CTG AAA TAT TTT
ATC AAT TTT TTT TTT TAT AAA TTC GGC CTG GAA ATT TGT TTT TTG ATG GCG
GTT AAT GTA ATC GGT CAA CGC ATG AAC TTT TTA GTT ACT CTG CAC GGT TGC
TGG CTC GTG GCG ATT CTT ACC CGC CGT CAT CGC CAG GCG ATC GCC CGT CTG
TGG CCG AAT TAT TGC TTA TTC CTT GCT CTG TTT CTG CTG TAT CAG TAT CTC
CTG TGC CTG GGC ATG CCG CCG GCG TTG TGC ATT GAT TAT CCT TGG CGG TGG
AGC CGT GCC GTA CCG ATG AAC AGC GCG CTT ATT AAG TGG CTG TAC TTA CCT
GAT TTC TTC CGT GCA CCG AAT TCG ACG AAC TTG ATC TCC GAT TTC CTG TTA
CTG TTG TGC GCG TCG CAA CAG TGG CAG GTG TTC TCG GCG GAA CGC ACA GAG
GAG TGG CAG CGC ATG GCC GGT GTA AAT ACC GAT CGC CTG GAA CCG CTC CGT
GGC GAA CCG AAT CCG GTG CCG AAT TTT ATT CAT TGT CGC AGT TAT TTA GAC
ATG TTG AAA GTT GCA GTA TTC CGC TAC CTG TTC TGG CTG GTA CTC GTT GTT
GTA TTC GTT ACT GGC GCG ACT CGG ATT AGT ATT TTC GGC TTA GGC TAT CTG
TTA GCC TGT TTT TAT CTG CTG CTT TTC GGT ACC GCA CTG CTG CAG CGC GAC
ACG CGT GCG CGC CTG GTT CTG TGG GAT TGC CTC ATT CTC TAT AAC GTG ACT
GTG ATT ATC AGT AAA AAC ATG CTT AGT TTG CTG GCG TGC GTT TTC GTT GAA
CAG ATG CAG ACC GGT TTT TGC TGG GTA ATC CAA TTA TTC TCA TTA GTG TGC
ACT GTG AAA GGC TAT TAC GAT CCG AAA GAA ATG ATG GAT CGG GAT CAG GAT
TGT TTG CTC CCG GTG GAA GAA GCA GGT ATT ATC TGG GAT TCT GTC TGT TTT
TTT TTC CTT TTA CTG CAG CGT CGC GTT TTC CTG TCC CAC TAC TAT CTG CAC
GTT CGG GCT GAT CTG CAG GCA ACC GCC CTT CTG GCC TCG CGG GGG TTT GCC
TTA TAT AAC GCC GCC AAT CTG AAA TCC ATT GAT TTC CAC CGT CGC ATT GAA
GAA AAG TCT CTG GCT CAA CTG AAA CGT CAG ATG GAA CGC ATT CGT GCC AAA
CAG GAG AAA CAT CGT CAA GGC CGC GTT GAT CGG AGT CGG CCG CAG GAT ACA
TTG GGC CCA AAG GAT CCA GGG CTG GAA CCG GGT CCG GAC TCG CCG GGC GGT
TCG TCC CCG CCG CGT CGT CAG TGG TGG CGG CCA TGG CTC GAT CAC GCT ACC
GTT ATC CAT AGT GGC GAT TAT TTT TTA TTT GAG TCC GAT TCG GAA GAA GAA
GAA GAA GCA GTT CCG GAG GAT CCG CGC CCT AGT GCA CAG AGC GCG TTT CAA
CTT GCG TAT CAG GCG TGG GTG ACC AAT GCA CAA GCC GTT TTG CGC CGC CGC
CAG CAG GAA CAG GAA CAG GCG CGC CAA GAA CAA GCA GGT CAA CTG CCT ACG
GGC GGC GGC CCG TCA CAA GAA GTT GAA CCT GCC GAA GGT CCG GAG GAA GCT
GCG GCC GGG CGC AGC CAT GTG GTG CAG CGC GTT CTT AGC ACC GCG CAG TTT
CTG TGG ATG CTG GGC CAA GCC CTG GTA GAT GAA TTG ACA CGC TGG TTG CAA
GAA TTT ACG CGT CAT CAC GGC ACC ATG TCC GAC GTG CTG CGC GCC GAG CGT
TAC TTG CTG ACG CAG GAG CTG TTG CAA GGG GGC GAA GTA CAC CGT GGC GTA
CTG GAC CAG CTC TAC ACA TCG CAA GCA GAG GCG ACG CTT CCT GGC CCA ACC
GAG GCC CCG AAC GCG CCA AGC ACC GTC TCT AGC GGC CTG GGC GCG GAA GAA
CCT TTA TCC TCC ATG ACA GAC GAT ATG GGG TCA CCG CTG AGC ACC GGT TAC
CAT ACC CGT TCG GGG TCT GAA GAG GCA GTT ACG GAC CCG GGT GAA CGC GAA
GCT GGT GCC TCT CTC TAT CAG GGG CTG ATG CGC ACC GCT TCA GAG CTG CTG
CTG GAT CGC CGC CTG CGC ATC CCT GAA CTG GAA GAA GCC GAA TTA TTT GCA
GAA GGC CAG GGT CGT GCC TTG CGC CTG TTA CGT GCA GTA TAT CAG TGC GTC
GCG GCA CAT AGC GAA CTG CTG TGT TAC TTT ATC ATT ATC CTG AAT CAT ATG
GTG ACC GCG TCT GCA GGT AGT CTG GTA CTG CCG GTT CTG GTA TTC TTA TGG
GCC ATG CTT TCC ATC CCG CGT CCA AGT AAA CGG TTC TGG ATG ACG GCG ATT
GTG TTT ACC GAA ATT GCT GTA GTG GTA AAA TAT TTA TTT CAA TTT GGC TTC
TTC CCA TGG AAT TCC CAC GTG GTG CTG CGG CGC TAT GAG AAT AAA CCG TAC
TTC CCT CCG CGC ATT TTG GGC TTA GAA AAA ACC GAT GGC TAT ATC AAA TAC
GAT TTA GTG CAG CTG ATG GCG TTA TTT TTT CAT CGC AGT CAG CTG TTA TGT
TAT GGT CTG TGG GAT CAT GAA GAG GAC TCT CCT AGC AAG GAA CAC GAT AAA
TCG GGT GAA GAA GAA CAG GGT GCC GAA GAA GGC CCT GGT GTG CCT GCA GCT
ACC ACT GAG GAT CAC ATT CAG GTG GAA GCG CGC GTT GGC CCA ACC GAT GGT
ACA CCG GAA CCG CAG GTG GAG TTA CGT CCG CGC GAT ACG CGT CGC ATT TCA
CTG CGT TTC CGT CGC CGT AAA AAA GAA GGC CCA GCG CGG AAG GGT GCT GCG
GCG ATC GAG GCA GAG GAC CGT GAG GAG GAG GAA GGG GAG GAA GAA AAA GAA
GCG CCA ACG GGC CGT GAG AAA CGT CCG TCG CGG TCT GGT GGC CGC GTT CGC
GCA GCT GGC CGT CGC CTG CAG GGG TTT TGC CTG TCA CTG GCG CAG GGT ACC
TAT CGC CCG CTC CGT CGC TTT TTC CAC GAT ATT CTG CAC ACG AAA TAT CGT
GCC GCG ACA GAT GTG TAT GCG CTG ATG TTT TTA GCT GAT GTG GTG GAT TTT
ATT ATT ATT ATC TTT GGG TTT TGG GCA TTC GGG AAG CAC TCT GCA GCA ACT
GAT ATT ACC TCT AGT TTA AGT GAT GAT CAG GTC CCG GAA GCG TTC CTG GTG
ATG CTG TTG ATT CAG TTT TCG ACG ATG GTT GTG GAT CGT GCT CTG TAT CTG
CGT AAG ACT GTC CTG GGT AAA TTG GCA TTT CAA GTG GCC TTA GTA TTG GCC
ATC CAT CTG TGG ATG TTC TTT ATT TTA CCG GCG GTG ACT GAA CGT ATG TTT
AAT CAG AAT GTT GTG GCC CAG TTA TGG TAT TTT GTG AAA TGT ATT TAC TTC
GCG TTA AGC GCG TAC CAA ATC CGG TGT GGT TAT CCG ACA CGT ATT CTG GGC
AAT TTC TTG ACT AAA AAA TAT AAC CAC CTT AAT CTG TTC CTG TTC CAA GGC
TTC CGC CTC GTT CCG TTT CTG GTG GAG TTA CGC GCA GTT ATG GAT TGG GTA
TGG ACA GAT ACT ACG CTG TCA CTC TCC TCG TGG ATG TGC GTG GAA GAT ATT
TAT GCT AAT ATT TTC ATC ATT AAA TGC TCG CGC GAA ACC GAG AAA AAG TAC
CCG CAA CCG AAA GGG CAA AAG AAA AAA AAA ATC GTG AAG TAT GGC ATG GGT
GGG TTA ATC ATT CTG TTC CTG ATT GCC ATC ATT TGG TTT CCG CTG TTG TTT
ATG TCA CTG GTG CGC TCG GTG GTG GGC GTG GTC AAT CAG CCG ATT GAT GTG
ACC GTG ACT TTG AAA TTA GGT GGC TAT GAA CCA TTG TTC ACG ATG AGT GCG
CAG CAA CCG AGT ATT ATT CCG TTT ACT GCG CAG GCG TAT GAA GAG CTG TCT
CGC CAG TTT GAT CCG CAA CCA CTG GCT ATG CAG TTT ATT TCC CAA TAT TCC
CCA GAG GAC ATC GTA ACT GCC CAG ATC GAG GGC AGC AGC GGC GCG CTG TGG
CGT ATT TCT CCT CCG AGT CGC GCC CAA ATG AAA CGC GAA CTG TAT AAT GGC
ACT GCC GAT ATC ACT CTT CGC TTC ACA TGG AAC TTT CAG CGG GAT CTG GCG
AAA GGC GGG ACC GTG GAA TAT GCG AAC GAG AAA CAT ATG TTG GCG CTG GCG
CCG AAC AGT ACC GCG CGT CGG CAA TTG GCC TCC TTG TTA GAG GGG ACC AGC
GAC CAA AGC GTA GTT ATC CCA AAC CTG TTT CCT AAA TAC ATT CGT GCG CCG
AAT GGT CCA GAG GCC AAC CCA GTC AAA CAA TTG CAA CCG AAT GAG GAG GCG
GAC TAT CTG GGC GTA CGT ATC CAA CTG CGT CGC GAA CAG GGT GCC GGC GCC
ACC GGC TTT CTG GAA TGG TGG GTA ATT GAA CTG CAG GAA TGC CGT ACG GAT
TGT AAT CTG CTC CCG ATG GTA ATT TTT TCG GAC AAA GTG AGC CCG CCG TCG
TTA GGT TTC TTA GCT GGT TAT GGC ATC ATG GGT TTG TAT GTT AGC ATC GTG
CTG GTC ATC GGG AAA TTT GTG CGC GGG TTT TTC AGC GAG ATT AGC CAT AGC
ATC ATG TTC GAG GAA CTT CCG TGT GTG GAT CGC ATC CTG AAG CTG TGC CAG
GAT ATC TTC TTA GTT CGC GAG ACC CGT GAA CTG GAA CTT GAA GAG GAA CTG
TAT GCC AAG CTG ATT TTC CTC TAC CGC TCC CCA GAA ACG ATG ATC AAA TGG
ACC CGT GAA AAA GAA

Key differences from human-optimized version: Arginine codons AGG/AGA → CGT/CGC (abundant E. coli tRNAs) · Leucine CTA → CTG/CTT · Isoleucine ATA → ATT · Lower GC content (~52% vs ~69% in human-optimized)


Quick Comparison

PropertyProteinNative DNAE. coli-Optimized DNA
Length2,521 aa7,566 bp7,566 bp
GC content~58%~52%
Target hostH. sapiensE. coli C43(DE3)
Rare codonsNone (native)Eliminated
Encoded proteinPIEZO1IdenticalIdentical

Note: Both DNA sequences encode the exact same protein. Only the synonymous codon choices differ, optimized for the translational machinery of the target host organism.

Week 3 HW: Lab Automation

Post Lab Questions

Write a description about what you intend to do with automation tools for your final project. You may include example pseudocode or Python scripts, procedures you may need to automate, 3D printed holders you may need, and more.

Example ideas that you can create a protocol for: Use the cloud laboratory to screen an array of biosensors constructs that you design, synthesize, and express using cell-free protein synthesis Use Opentrons to dispense microorganisms onto fabric to design “living textiles” as “bio artwork”

Find and briefly summarize a published paper that utilizes laboratory automation to achieve novel biological applications Include in your summary: General overview (2 paragraphs) Findings (1 paragraph) Relevant Figures (1 - 2 max)

Week 4 HW: Protein Design Part I

Part A Conceptual Questions

Q1. How many molecules of amino acids do you take in with a piece of 500 g of meat?

Meat is approximately 25% protein by weight, so 500 g of meat contains about 125 g of protein. Using the given average molecular weight of ~100 Da (= 100 g/mol) per amino acid:

$500\text{ g} \times 0.25 = 125\text{ g of protein}$

Moles of amino acids = 125 g ÷ 100 g/mol = 1.25 mol

Number of molecules = 1.25 mol × 6.022 × 10²³ mol⁻¹ ≈ 7.5 × 10²³ amino acid molecules


Q2. Why do humans eat beef but do not become a cow, eat fish but do not become fish?

Proteases break dietary proteins down into individual amino acids during digestion, which are chemically identical regardless of source. Once absorbed, your cells reassemble these amino acids into human proteins according to the instructions in your own DNA. No genetic information transfers from food to your genome; dietary DNA is degraded by nucleases in the gut. Food provides raw building blocks, but your genome provides the blueprint, so the output is always human protein.


Q3. Why are there only 20 natural amino acids?

The 20 canonical amino acids provide a near-optimal coverage of side-chain chemical properties — spanning small to large, polar to nonpolar, charged, aromatic, and nucleophilic — with minimal redundancy. The triplet genetic code can encode 64 codons, and after reserving stop signals and building in redundancy to buffer against mutation errors, 20 amino acids strikes a good balance between functional diversity and error tolerance. These 20 are also the ones that were biosynthetically accessible through early metabolic pathways derived from central metabolites. Once the translation machinery co-evolved around this set, changing it became prohibitively costly since it would affect every protein in every organism, so the system became frozen early in evolution.


Q4. Where did amino acids come from before enzymes that made them, and before life started?

Amino acids predate life and arise from chemistry. The Miller–Urey experiment demonstrated that electric discharges through a reducing atmosphere produce glycine, alanine, aspartate, and other amino acids. Life inherited these building blocks from prebiotic geochemistry and later evolved enzymatic pathways to produce them more efficiently.


Q5. If you make an α-helix using D-amino acids, what handedness would you expect?

A left-handed α-helix. The natural right-handed α-helix arises because L-amino acids position their side chains to minimize steric clashes with backbone carbonyls specifically in the right-handed conformation. D-amino acids are the mirror image of L-amino acids, so the favorable backbone dihedral angles flip sign — from (−57°, −47°) to (+57°, +47°) — producing a left-handed helix. This is confirmed experimentally: synthetic D-peptides give circular dichroism spectra that are exact mirror images of natural L-peptide helices.


Q6. Can you discover additional helices in proteins?

Yes. (according to google) Beyond the common α-helix, proteins contain 3₁₀-helices (3.0 residues/turn, i→i+3, common at helix termini), π-helices (4.4 residues/turn, i→i+5, rare single-turn insertions), and the collagen triple helix. In principle, any repeating set of backbone (φ, ψ) angles that permits regular hydrogen bonding defines a helix, and the main candidates have been systematically mapped from the Ramachandran plot.


Q7. Why are most molecular helices right-handed?

The dominance of right-handed helices stems from the universal use of L-amino acids–> the lowest-energy conformation due to favorable side-chain positioning.

Once L-amino acids became dominant, all downstream molecular machinery co-evolved around that chirality. If life had been founded on D-amino acids, left-handed helices would dominate and the biology would be equally functional.


Q8. Why do β-sheets tend to aggregate? What is the driving force?

β-sheets are inherently open-ended structures: unlike α-helices where all backbone hydrogen-bond donors and acceptors are satisfied internally, β-sheet edge strands have one face of exposed N–H and C=O groups available for hydrogen bonding with additional strands. This creates a thermodynamic driving force to recruit more strands and extend the sheet. The main forces driving aggregation are backbone hydrogen bonding between exposed edges, essentially intermolecular β-sheet extension, the hydrophobic effect from burying nonpolar side chains between stacked sheets, and van der Waals contacts in the cross-β arrangement.


Q9. Why do many amyloid diseases form β-sheets? Can you use amyloid β-sheets as materials?

Proteins involved in amyloid diseases have aggregation-prone hydrophobic stretches or destabilizing mutations that lower the kinetic barrier to reaching this state, and once a nucleus forms it templates further conversion in a self-propagating manner.

Amyloid fibrils can be used as materials. They have tensile strength comparable to steel and Young’s moduli of 2–14 GPa, and they resist proteases, detergents, and heat. In bionanotechnology, amyloid fibrils serve as scaffolds for conductive nanowires, hydrogel matrices for tissue engineering and drug delivery, and membranes for heavy-metal water purification.


Part B — Protein Analysis and Visualization


Q1. Briefly describe the protein you selected and why you selected it.

PIEZO1 is a homotrimeric mechanosensitive ion channel that converts physical forces — such as fluid shear stress, membrane stretch, and compressive pressure — into biochemical signals by allowing cation influx (primarily Ca²⁺) upon mechanical stimulation. Each subunit contains ~38 transmembrane helices that form a distinctive curved, propeller-like architecture with three peripheral “blades” and a central pore.

PIEZO1 is valuable because it serves as a fundamental mechanical switch for cellular programming: it governs processes including vascular development, red blood cell volume regulation, blood pressure sensing, and cell lineage determination in stem cells.


Q2. Identify the amino acid sequence of your protein.

Sequence length and composition

  • Length: 2,521 amino acids (human PIEZO1, UniProt Q9H5I5).
  • Most common amino acid: Leucine (L), appearing 367 times (~14.6% of the sequence). This is expected — leucine is the most abundant residue in transmembrane α-helices due to its hydrophobic character and favorable helix-forming propensity, and PIEZO1 is overwhelmingly α-helical with ~38 transmembrane passes per subunit.

Homologs

Using UniProt BLAST on the human PIEZO1 sequence returns homologs across a broad range of eukaryotes — vertebrates, insects, plants, and even single-celled eukaryotes — reflecting the ancient evolutionary origin of mechanosensation. The closest homolog is PIEZO2 (human, ~42% sequence identity), which mediates light touch and proprioception. Beyond PIEZO2, orthologs of PIEZO1 are found in most metazoan genomes (mouse, zebrafish, Drosophila, C. elegans), with more distant homologs in plants (Arabidopsis) and protists. A typical BLAST search returns several hundred significant hits (E-value < 0.05), though the number depends on the database and threshold used.

Protein family

PIEZO1 belongs to the Piezo family , a eukaryote-specific family of mechanosensitive channels with no significant homology to any other known ion channel family (e.g., TRP channels, Degenerin/ENaC, or MscL/MscS bacterial mechanosensitive channels). This makes the Piezo family an evolutionarily independent solution to mechanotransduction.


Q3. Identify the structure page of your protein in RCSB. Structure and resolution

The primary full-length structure is PDB: 5Z10 . The human PIEZO1 also has related entries (e.g., PDB 7WLT).

  • Resolution: 3.97 Å. For a cryo-EM structure of a ~900 kDa trimeric membrane protein, this is a reasonable resolution — sufficient to trace the backbone, assign secondary structure, and identify transmembrane helix positions. However, it is not high resolution by crystallographic standards; individual side-chain conformations and water molecules are generally not resolvable at this resolution.

Other molecules in the structure

The solved structure contains:

  • Lipid molecules — Phospholipids are resolved in the transmembrane domain, consistent with PIEZO1’s curved membrane-embedded architecture and its sensitivity to membrane composition and tension.
  • Detergent molecules — from the purification process (typically digitonin or LMNG).
  • Ions — depending on the specific entry, Ca²⁺ or other cations may be modeled in or near the pore region.

Structure classification

In the RCSB classification, it falls under membrane proteins → ion channels → mechanosensitive channels. Its unique propeller-blade topology does not closely resemble any other structurally characterized ion channel family, making it a distinct structural class.


Q4. Visualize the structure of your protein.

Visualize the protein as “cartoon”, “ribbon” and “ball and stick”.

Cartoon

Ribbon

Ball and Stick

Secondary structure

PIEZO1 is overwhelmingly α-helical. Each subunit contains ~38 transmembrane helices organized into repeated structural units called “Piezo repeats” (or “transmembrane helical units”), which form the curved blades of the propeller. The central pore region includes an inner helix (TM37), outer helix (TM38), and the C-terminal extracellular domain (CED). There are virtually no β-sheets in the structure — only short loops and turns connect the helices. This extreme α-helical bias is consistent with its identity as a multi-pass transmembrane protein.

Residue type distribution (hydrophobic vs. hydrophilic)

When colored by residue type:

  • The transmembrane blade regions are dominated by hydrophobic residues (Leu, Ile, Val, Phe, Ala) — these face the lipid bilayer and form the core of helix-helix packing within the membrane. This explains why leucine is the most frequent amino acid.
  • Hydrophilic and charged residues (Arg, Lys, Glu, Asp) are concentrated at the intracellular and extracellular surfaces, at helix termini (anchoring the protein at the membrane-water interface), and lining the central ion conduction pore (where they contribute to ion selectivity and gating).
  • The CED (C-terminal extracellular domain), which protrudes above the membrane at the trimer center, has a higher proportion of polar and charged residues, consistent with its aqueous environment.

This distribution follows the classic “positive-inside rule” — positively charged residues (Arg, Lys) are enriched on the cytoplasmic side of the membrane.

Surface and binding pockets

The surface of PIEZO1 reveals several notable features:

  • Central pore. The most prominent “hole” is the ion conduction pathway at the trimer axis. This is the functional pore through which cations flow upon channel activation.
  • Lateral fenestrations. Between the blade domains near the membrane plane, there are openings (fenestrations) that may allow lateral lipid access to the pore — a feature shared with some other ion channels and potentially important for lipid-mediated gating.
  • Intracellular “cap” cavity. On the cytoplasmic face, the converging beam-like structures create an enclosed cavity that has been proposed as a binding site for intracellular modulators.
  • Yoda1 binding site. The small-molecule agonist Yoda1 binds in a pocket between the blade and pore module (identified in structures like PDB 7WLT), confirming a druggable pocket in the structure.

Overall, the surface is not smooth — the curved, dome-shaped architecture creates multiple grooves and pockets that are functionally relevant for lipid interaction, mechanical force transduction, and pharmacological targeting.

Part C - Using ML-Based Protein Design Tools


1. Deep Mutational Scans

1.1 Method

ESM2 was used to generate an unsupervised deep mutational scan of human PIEZO1 (UniProt Q9H5I5, 2,521 amino acids). For every position in the sequence, the model scores the log-likelihood of substituting the wild-type residue with each of the 20 amino acids. The resulting heatmap displays Model Scores across all positions (x-axis) and all possible amino acid substitutions (y-axis), where green/yellow indicates neutral or favorable substitutions and dark blue/purple indicates substitutions the model predicts to be strongly deleterious.

1.2 Observed Patterns

Conserved positions appear as dark vertical columns. Several positions show strongly negative scores across nearly all 20 substitutions, indicating that the model considers any change at those positions highly unlikely based on evolutionary sequence patterns. These columns correspond to residues that are critical for PIEZO1’s structure or function — they map primarily to the pore-lining region and the C-terminal anchor domain, where even conservative substitutions would disrupt ion conduction or mechanical gating.

The Leucine (L) row is notably bright across most positions. Mutations to leucine are generally well-tolerated, which is consistent with PIEZO1’s identity as a multi-pass transmembrane protein (~38 TM helices per subunit). Leucine is the most common residue in α-helical transmembrane domains due to its hydrophobic character and favorable helix-forming propensity, so substituting to leucine is a “safe” change at most positions.

The Glycine (G) row shows scattered deep blue spots. Positions where the wild-type is glycine tend to show dark columns across other substitutions. Glycines in transmembrane helices are critical for helix packing and flexibility — they allow tight inter-helix contacts that bulkier residues would sterically prevent. Mutating these glycines is therefore strongly disfavored.

A specific example: One of the most prominent dark vertical bands appears in the region corresponding to the inner pore helix of PIEZO1. Conserved charged residues in this region (e.g., glutamate or arginine residues lining the pore) score very negatively when mutated to hydrophobic residues like leucine, isoleucine, or valine. This is biologically expected — charged residues in the pore domain are essential for cation selectivity and gating, and replacing them with hydrophobic side chains would destroy channel function.


2. Latent Space Analysis

2.1 Method

15,177 structurally classified protein domains from the SCOPe/ASTRAL database were embedded using ESM2-8M (hidden dimension = 320) into 320-dimensional vectors. t-SNE then projected these into 3D for visualization. The color scale represents TSNE3 (yellow = high, purple = low), providing visual depth. Despite using the smallest ESM2 model, the projection recovers meaningful structural groupings, demonstrating that protein language models encode structural information implicitly from sequence alone.

2.2 Neighborhood Analysis

I took three corresponding coordinates for analysis:

Upper yellow region (high TSNE3) — β-sheet-rich proteins.

  • d2g5da1 (TSNE: −2.29, −1.13, 4.05) is Membrane-bound lytic murein transglycosylase A (MLTA) from Neisseria gonorrhoeae. Its neighbors in this yellow cluster are predominantly other β-barrel and β-sheet-rich domains, including outer membrane proteins from gram-negative bacteria that share the β-barrel architecture.

Dense central orange region (intermediate TSNE3) — common α/β folds.

  • d3cwna_ (TSNE: −0.82, 0.88, 0.34) is an E. coli protein matching SCOP class c.1.10.1 (α/β, TIM barrel fold). The TIM barrel is the most common enzyme fold in nature (found in glycolysis enzymes, aldolases, tryptophan synthase, etc.), and its position in the densest part of the plot reflects both its abundance in protein databases.

Lower purple region (low TSNE3) — unusual/transmembrane proteins.

  • d1x2ma1 (TSNE: −0.79, 0.85, −6.20) is Lag1 longevity assurance homolog 6 (LASS6/CerS6) from mouse. LASS6 is a multi-pass transmembrane ceramide synthase with ~5–6 TM helices and a unique Lag1p motif. Its position far from the soluble enzyme core reflects ESM2’s recognition that its hydrophobic, membrane-spanning sequence features are fundamentally distinct from typical soluble proteins.

2.3 Placing PIEZO1

PIEZO1 would be expected to sit in the purple periphery or as an isolated outlier given that

  • It is an extremely large multi-pass transmembrane protein, so its sequence composition is heavily biased toward hydrophobic residues. This transmembrane character would push it away from the soluble-protein-dominated central core, similar to how LASS6 sits in the purple region.

  • PIEZO1 has no sequence homology to any other known ion channel family. Its “Piezo repeat” domains and propeller-blade architecture are structurally unique. ESM2 would therefore embed it far from other channel proteins.

  • The only protein expected to sit nearby is PIEZO2 (~42% sequence identity), the sole close homolog. If PIEZO2 is absent from the dataset, PIEZO1 would sit alone — reflecting the evolutionary isolation of the Piezo family as a structurally novel, independent solution to mechanosensation.

Week 5 HW: Protein Design Part II

Part A SOD1 Binder Peptide Design

Part 1: Generate Binders with PepMLM

Human SOD1 Sequence (UniProt)

MATKAVCVLKGDGPVQGIINFEQKESNGPVKVWGSIKGLTEGLHGFHVHEFGDNTAGCTSAGPHFNPLSRKHGGPKDEERHVGDLGNVTADKDGVADVSIEDSVISLSGDHCIIGRTLVVHEKADDLGKGGNEESTKTGNAGSRLACGVIGIAQ

A4V Mutant Sequence

Position 4: Ala → Val (A4V)

MATKVVCVLKGDGPVQGIINFEQKESNGPVKVWGSIKGLTEGLHGFHVHEFGDNTAGCTSAGPHFNPLSRKHGGPKDEERHVGDLGNVTADKDGVADVSIEDSVISLSGDHCIIGRTLVVHEKADDLGKGGNEESTKTGNAGSRLACGVIGIAQ
PositionWild-typeMutant
4A (Ala)V (Val)

PepMLM-Generated Peptides

4 candidate binders generated against the A4V mutant sequence + the known reference peptide.
Lower perplexity scores indicate sequences more confidently predicted by the model.

#SequencePerplexityNote
PepMLM 1WHYPAAAAAWKK8.611
PepMLM 2WRSPAVAAAHKE7.866Lowest perplexity
PepMLM 3WRYPAVALEWKK16.562Highest perplexity
PepMLM 4WHSYVVGARWWK13.338
KnownFLYRWLPSRRGGReference binder

Note on Perplexity: In PepMLM, perplexity reflects how confidently the masked language model predicts each residue in context. Lower perplexity suggests the sequence is more consistent with the model’s learned distribution of binders; however, higher perplexity sequences may still yield productive binding if their physicochemical and structural properties are favourable.

Part 2: Evaluate Binders with AlphaFold 3


For the sake of my OCD
or else with only 5 pics will look ugly

Known Peptide
ipTM = 0.36

Peptide 1
ipTM = 0.27

Peptide 2
ipTM = 0.40

Peptide 3
ipTM = 0.19

Peptide 4
ipTM = 0.39

ipTM (interface predicted TM-score) measures predicted interface accuracy.
Values range from 0 to 1 — higher is better. Scores ≥ 0.5 generally indicate confident predictions.


Binding Analysis

StructureipTMNear A4V / N-term?β-barrel engagementSurface character
Known (Reference)0.36YesLateral strand edgeSurface-bound, extended
PepMLM Peptide 10.27NoMinimalSurface, poorly engaged
PepMLM Peptide 20.40Partial — dimer faceLateral interface cleftSurface docked
PepMLM Peptide 30.19NoNonePeripheral, non-specific
PepMLM Peptide 40.39Distal (C-term base)Bottom loop regionSurface-bound

Notes

  • PepMLM Peptide 2 is the strongest candidate: highest ipTM, adopts α-helical secondary structure upon binding, and docks into the concave groove at the lateral β-barrel interface — the region destabilised by the A4V mutation. One face of the helix contacts SOD1 while the other remains solvent-exposed. This binding mode is consistent with therapeutic peptides that stabilise misfolding-prone interfaces.
  • PepMLM Peptide 4 has a comparable ipTM (0.39) but localises to the base of the barrel near C-terminal loops, distal from the A4V site, limiting its therapeutic relevance.
  • PepMLM Peptides 1 and 3 show poor interface engagement and are unlikely to be productive binders.

ipTM (interface predicted TM-score) measures predicted interface accuracy.
Values range from 0–1; scores ≥ 0.5 generally indicate confident predictions. All values here are modest, consistent with flexible peptide–protein interfaces typical in AlphaFold-Multimer assessments.


Part 3: Evaluate Properties of Generated Peptides in the PeptiVerse

swipe left for more

PepMLM 1
WHYPAAAAAWKK
PepMLM 2
WRSPAVAAAHKE
PepMLM 3
WRYPAVALEWKK
PepMLM 4
WHSYVVGARWWK
Known (Reference)
FLYRWLPSRRGG
PropertyPredictionValue
💧 SolubilitySoluble1.000
🩸 HemolysisNon-hemolytic0.013
🔗 Binding AffinityWeak binding4.902 pKd/pKi
📏 Length12 aa
⚖️ Mol. Weight1399.6 Da
⚡ Net Charge+1.84
🎯 pI9.70 pH
💦 GRAVY−0.56
PropertyPredictionValue
💧 SolubilitySoluble1.000
🩸 HemolysisNon-hemolytic0.016
🔗 Binding AffinityWeak binding4.661 pKd/pKi
📏 Length12 aa
⚖️ Mol. Weight1322.5 Da
⚡ Net Charge+0.85
🎯 pI8.76 pH
💦 GRAVY−0.58
PropertyPredictionValue
💧 SolubilitySoluble1.000
🩸 HemolysisNon-hemolytic0.027
🔗 Binding AffinityWeak binding5.784 pKd/pKi
📏 Length12 aa
⚖️ Mol. Weight1546.8 Da
⚡ Net Charge+1.76
🎯 pI9.70 pH
💦 GRAVY−0.74
PropertyPredictionValue
💧 SolubilitySoluble1.000
🩸 HemolysisNon-hemolytic0.039
🔗 Binding AffinityWeak binding6.308 pKd/pKi
📏 Length12 aa
⚖️ Mol. Weight1574.8 Da
⚡ Net Charge+1.85
🎯 pI9.99 pH
💦 GRAVY−0.55
PropertyPredictionValue
💧 SolubilitySoluble1.000
🩸 HemolysisNon-hemolytic0.047
🔗 Binding AffinityWeak binding5.968 pKd/pKi
📏 Length12 aa
⚖️ Mol. Weight1507.7 Da
⚡ Net Charge+2.76
🎯 pI11.71 pH
💦 GRAVY−0.71

All peptides are predicted soluble and non-hemolytic. Binding affinity (pKd/pKi): higher = stronger predicted affinity. Negative GRAVY scores reflect hydrophilic character across all sequences. Across the five peptides, there is no clear correlation between ipTM and predicted binding affinity.

The peptide I selected is PepMLM Peptide 2 (WRYPAVALEWKK). While its predicted affinity is modest, it has the highest ipTM, adopts stable α-helical secondary structure upon docking — a hallmark of productive peptide–protein interfaces — and engages the lateral cleft of the β-barrel at precisely the region destabilised by A4V. It is the only candidate where the structural, physicochemical, and site-specificity evidence converge.


Part C: Final Project: L-Protein Mutants

The MS2 bacteriophage lysis protein (L-protein) is a 74 amino acid protein responsible for killing E. coli host cells by perforating the bacterial membrane. A critical vulnerability of this system is that a single point mutation in the host chaperone protein DnaJ can prevent the lysis protein from functioning, allowing E. coli to acquire resistance to MS2.

The L-protein has two structurally and functionally distinct regions:

  • Soluble N-terminal domain (positions 1–38): responsible for interaction with DnaJ
  • Transmembrane domain (positions 39–73): responsible for membrane insertion and lysis

At least 2 in the transmembrane region and at least 2 in the soluble region.

Option 1: Mutagenesis

Running the ESM-2 protein language model (facebook/esm2_t6_8M_UR50D) on the full wild-type L-protein sequence:

METRFPQQSQQTPASTNRRRPFKHEDYPCRRQQRSSTLYVLIFLAIFLSKFTNQLLLSLLEAVIRTVTTLQQLLT

The model scores every possible single amino acid substitution at every position using a Log Likelihood Ratio (LLR):

  • Positive score → the substitution looks evolutionarily natural and compatible
  • Negative score → the substitution disrupts what the model expects at that position
  • Position 1 (M) showed almost entirely dark purple scores, confirming the start methionine is essential and should not be mutated
  • Rows M, W, Y were dark across most positions — large/bulky amino acids are generally disruptive substitutions
  • The transmembrane region (~positions 39–73) showed brighter yellow/green scores for hydrophobic substitutions (L, I, V, F) — consistent with the hydrophobic nature of membrane-spanning helices
  • Bright yellow hotspots at positions 29, 39, and 50 stood out as positions where specific mutations are strongly predicted

The notebook was first run with a focused query on the transmembrane region (positions 38–60), producing the following top-scored mutations:

  Amino Acid  Position     Score
0           L        50  2.561468
1           L        39  2.241780
2           I        50  1.928801
3           L        53  1.864932
4           L        52  1.813968
5           F        50  1.802069
6           V        50  1.594576
7           S        50  1.574557
8           L        45  1.539248
9           S        39  1.517457
10          L        40  1.477630
11          A        39  1.364999
12          A        50  1.357795
13          I        39  1.320103
14          T        39  1.302804
15          F        39  1.245851
16          V        39  1.244390
17          T        50  1.222131
18          L        54  1.120860
19          R        39  1.064191

Three positions dominate the top scores: 50, 39, and 45. The model strongly favors leucine (L) substitutions at positions 50 and 39, and also at position 45. This is the first signal pointing toward K50L, Y39L, and A45(L or P) as strong TM candidates. Notably, multiple substitutions at position 50 rank highly (L, I, F, V, S, A),suggesting this position is generally flexible — but leucine scores the highest of all.


The notebook was then run on the full protein sequence to get a global ranking across all 74 positions:

     Position Wild_Type_AA Mutation_AA  LLR_Score
989         50            K           L   2.561468
574         29            C           R   2.395427
769         39            Y           L   2.241780
575         29            C           S   2.043150
173          9            S           Q   2.014325
573         29            C           Q   1.997049
572         29            C           P   1.971029
569         29            C           L   1.960646
987         50            K           I   1.928801
1049        53            N           L   1.864932

The top 10 globally are dominated by three positions: 50 (K→L), 29 (C→R/S/Q/P/L), and 39 (Y→L). This globally confirms what the TM scan already suggested, and additionally highlights C29 in the soluble region as a computationally interesting mutation site.

The full ranking also produced a second merged output combining both score datasets:

     Position Wild_Type_AA Mutation_AA  LLR_Score
1332        50            K           L   2.561468
770         29            C           R   2.395427
1035        39            Y           L   2.241780
229          9            S           Q   2.014325
776         29            C           Q   1.997049
...

The computational shortlist from the ESM model was:

  • K50L (score: +2.56) — highest in entire protein
  • C29R (score: +2.40) — highest in soluble region
  • Y39L (score: +2.24) — strong TM candidate
  • A45L (score: +1.54) — noted in TM scan

The L-Protein Mutants CSV was uploaded into the notebook, which displayed the first rows of the experimental dataset:

| Position | Base Pair Changed | AA Position | AA Change  | Lysis | Protein Level |
|----------|------------------|-------------|------------|-------|---------------|
| 3        | G->T              | 1           | M->I       | 0     | 0             |
| 3        | G->A              | 1           | M->I       | 0     | 0             |
| 2        | T->C              | 1           | M->T       | 0     | 0             |
| 4        | G->T              | 2           | E->Stop    | 0     | N.D.          |
| 8        | C->T              | 3           | T->I       | 0     | 0             |

This dataset contains experimentally measured lysis outcomes (0 = no lysis, 1 = lysis) for mutations that have already been tested in the lab. Cross-referencing this with the ESM scores revealed which computational predictions align with real biology.


Merging both datasets exposed a critical finding: the ESM model only partially agrees with experimental lysis outcomes.

MutationESM ScoreLysis (Lab)Agreement?
P13L+0.10Yes
S15A+0.04Yes
K23E+0.18Yes
E25G+0.45Yes
A45P+0.04Yes
I46F-0.10Yes
R18G-0.85Yes
R31I-0.93Yes
L44P-1.59Yes
R20W-2.18Yes

The disagreements (especially R18G, I46F, L44P) suggest that the ESM model scores general protein structural fitness (the ability to fold into a stable, functional, three-dimensional shape (conformation) that is energeticaly favorable), not functional lysis activity (the process of breaking open cell membranes).

Mutations that disrupt DnaJ binding (like R18G) are penalised by the model because the arginine is evolutionarily conserved — but conserved because it binds DnaJ.

This insight shaped the final selection strategy:

Use ESM scores to identify novel untested candidates with high computational confidence, and use experimental data to validate or override those scores based on known biology.


With all evidence assembled, five mutations were selected spanning both protein regions:

Soluble Region Mutations (Positions 1–38)

P13L — Position 13, Proline → Leucine

  • ESM Score: +0.10 | Lysis: Confirmed | Protein Level: Confirmed
  • Proline at position 13 creates a rigid backbone kink within the DnaJ-binding domain. Replacing it with leucine (flexible, hydrophobic) removes this constraint, potentially allowing the soluble domain to fold independently of DnaJ. Supported by both model and lab.

S15A — Position 15, Serine → Alanine

  • ESM Score: +0.04 | Lysis: Confirmed | Protein Level: Confirmed
  • Serine at position 15 sits within the NRRRP arginine-rich DnaJ-binding motif. Its hydroxyl side chain is a candidate hydrogen-bonding contact point with DnaJ. Replacing it with alanine (no side chain beyond a methyl group) directly removes a potential DnaJ interaction site. Both ESM and lab confirm this is tolerated. Selected alongside P13L because the two mechanisms are complementary — P13L addresses backbone rigidity, S15A addresses the interaction surface.

Transmembrane Region Mutations (Positions 39–73)

Y39L — Position 39, Tyrosine → Leucine

  • ESM Score: +2.24 | Lysis: Not yet tested
  • Position 39 is the first residue of the transmembrane domain — the boundary point where the protein transitions from soluble to membrane-spanning. Tyrosine is large and polar (hydroxyl group), which is chemically unusual at the start of a hydrophobic TM helix. Leucine is hydrophobic and small, making for a cleaner, sharper TM helix start. The ESM model strongly favors this change, and it ranked 3rd globally across the entire protein. The only tested mutation at this position (Y39H) failed — but histidine is charged and polar, making it incomparable to leucine. Selected as the highest-confidence novel TM candidate.

A45P — Position 45, Alanine → Proline

  • ESM Score: +0.04 | Lysis: Confirmed | Protein Level: Confirmed
  • Introducing proline into a transmembrane helix creates a structural kink — a feature found in many natural pore-forming proteins and ion channels. This kink at position 45 (sitting centrally in the TM helix) may promote the conformational change needed to open the transmembrane pore. Supported by both the ESM model and direct experimental confirmation.

K50L — Position 50, Lysine → Leucine

  • ESM Score: +2.56 (highest in entire protein) | Lysis: Not yet tested
  • Lysine (K) is a charged, hydrophilic amino acid — unusual to find it buried deep in a hydrophobic transmembrane helix. The ESM model assigns the highest score in the entire protein to replacing it with leucine (hydrophobic), which is thermodynamically much more compatible with a membrane environment. This substitution could improve membrane insertion efficiency, increase protein expression, or stabilize the TM assembly. It is acknowledged that four other K50 variants (K50E, K50N, K50I, K50Q) have failed in the lab, suggesting this position may be sensitive. However, K50L is specifically a hydrophobic substitution — chemically distinct from the charged/polar variants that failed — and its extremely high ESM score justifies testing it as a novel candidate.

Final Mutations

#MutationRegionESM ScoreLysisProteinRationale
1P13LSoluble+0.10Removes proline kink; enables DnaJ-independent folding
2S15ASoluble+0.04Removes DnaJ contact site within NRRRP motif
3Y39LTM+2.24Sharpens TM helix entry; 3rd highest ESM score globally
4A45PTM+0.04Proline kink promotes pore-forming conformation
5K50LTM+2.56Highest ESM score in protein; removes charged residue from TM core

AI Prompt used in this section for mutation selection: Given the provided mutations, could you explain the rationale behind each and why would each serve as potentially candidates?

Week 6 HW: Genetic Circuits Part I

DNA Assembly Questions

  1. What are some components in the Phusion High-Fidelity PCR Master Mix and what is their purpose?
  • Phusion DNA Polymerase: Building enzyme that reads the original DNA and constructs the new copies with high accuracy.
  • nucleotides
  • Optimized reaction buffer: A liquid that maintains the perfect chemical environment and pH for the enzyme to work.
  • MGCL2: Helper molecule (cofactor) that the polymerase needs to function properly.
  1. What are some factors that determine primer annealing temperature during PCR?
  • Primer Length: Longer primers have more binding area, so they also require higher temperatures.
  • GC Content: The DNA bases Guanine (G) and Cytosine (C) bind to each other with three chemical bonds, while Adenine (A) and Thymine (T) only use two. Therefore, primers with more Gs and Cs hold on tighter and require a higher temperature.
  1. There are two methods from this class that create linear fragments of DNA: PCR, and restriction enzyme digests. Compare and contrast these two methods, both in terms of protocol as well as when one may be preferable to use over the other.
  • PCR Protocol: Uses heat cycles to melt DNA apart, lets primers attach, and uses an enzyme to build new copies.
    • When to use: When you have a tiny amount of DNA and need billions of copies of a very specific segment, or when you want to add custom ends to a DNA sequence.
  • Restriction Digest Protocol: Mixes DNA with restriction enzymes and incubates them at a steady temperature. The enzymes physically cut the DNA at specific sequences.
    • When to use: When you want to extract a specific chunk of DNA out of a larger, already-existing piece, or when you want to verify that a DNA sequence is correct by seeing what sizes it cuts into.
  1. How can you ensure that the DNA sequences that you have digested and PCR-ed will be appropriate for Gibson cloning?
  • Must design the PCR primers so that the ends of DNA pieces overlap. The tail end of piece A must have the exact same sequence (usually 15 to 40 base pairs) as the starting end of piece B. The Gibson mix will chew back one strand of these ends, allowing the matching sequences to find each other and stick together like perfect puzzle pieces.
  1. How does the plasmid DNA enter the E. coli cells during transformation?
  • Usually through heat shock or electroporation. Heat Shock (Chemical): The bacteria are treated with chemicals (like calcium) to neutralize their charge, then subjected to a sudden spike in heat. This sudden temperature change creates temporary “pores” or holes in the bacterial wall, allowing the DNA to slip inside. Electroporation: The bacteria are hit with a quick zap of electricity, which shocks the cell membrane into opening those temporary pores.
  1. Describe another assembly method in detail (such as Golden Gate Assembly)
  • Golden Gate assembly is a method for joining multiple DNA fragments together in a single tube. It uses special “molecular scissors” called Type IIS restriction enzymes. Unlike normal restriction enzymes that cut exactly where they bind, Type IIS enzymes bind to a recognition sequence but reach over and cut the DNA a few steps away. Because they cut outside their recognition site, they leave behind custom “sticky ends” (overhangs) that you can design to match perfectly with the next piece of DNA. When the matching pieces snap together, an enzyme called ligase glues them shut permanently. Crucially, the original enzyme recognition site is cut off and left behind in this process, meaning the final assembled DNA has no “scars” or unwanted leftover sequences. Because the assembled product can no longer be cut by the enzyme, the cutting and gluing can happen simultaneously in one reaction tube.
  • Model this assembly method with Benchling or Asimov Kernel!

Asimov Kernel

https://kernel.asimov.com/htgaa-2026/repositories/repository/f59f227b-ac6a-476f-9705-03c135befd90/folder/a0348176-f25c-44d5-ba5e-1380c12580ea

  • Recreate the Repressilator in that empty Construct by using parts from the Characterized Bacterial Parts repository
  • Confirm it works as expected by running the Simulator (“play” button) and compare your results with the Repressilator Construct found in the Bacterial Demos repository
  • Document all of this work in your Notebook entry - you can copy the glyph image and the simulator graphs, and paste them into your Notebook

Construct Glyphs

Model — color-coded cassettes, includes pUC-SpecR v1 backbone
My Build — same 3 cassettes, no backbone, monochrome glyphs

Simulation Results

Model — 24h, clean phase separation, transcripts named by repressor
My Build — 72h, oscillation sustained but curves heavily overlapping
ModelMy Build
BackbonepUC-SpecR v1 includedNot added
Duration24 hours72 hours
OscillationClear phase separation between curvesSustained but three curves blur together
RNAP flux patternStepped bars (1.57 / 0.65 / 2.87)Similar stepped pattern (3.1 / 1.25 / 0.65)
Noise bandsModerate spreadWider spread
  • Build three of your own Constructs using the parts in the Characterized Bacterials Parts Repo
  • Explain in the Notebook Entry how you think each of the Constructs should function
  • Run the simulator and share your results in the Notebook Entry

Three Custom Constructs

1 — Toggle Switch
pTetR → LacI → represses pLacI
pLacI → TetR → represses pTetR

Two cassettes mutually silence each other. The system snaps to one of two stable states — either LacI is high and TetR is low, or vice versa. Acts as a bistable memory switch: once flipped, it holds its state.

No → bistable lock
Expect: one protein high, one flat zero

2 — NOR Gate
pAmtR → AmtR ⟐ pPsrA → PsrA
Both repress pAmeR → LambdaCI

Two input repressors each independently silence the output promoter pAmeR. LambdaCI is only produced when neither AmtR nor PsrA is present — a true NOR logic gate.

A=0, B=0 → Output ON
A=1 or B=1 → Output OFF

3 — Inducible Reporter
pAmtR → AmtR → represses pPsrA
pPsrA → PsrA → represses pAmeR → LambdaCI

A two-stage repression cascade. When the upstream signal (pAmtR) is active, it silences the chain, keeping output OFF. Remove the signal → repression lifts through both stages → LambdaCI output turns ON.

Signal present → Output OFF
Signal removed → Output ON

Toggle SwitchNOR GateInducible Reporter
Cassettes233
LogicBistable memoryNOR (A=0 AND B=0)Signal-gated ON/OFF
Output when inputs silentLocked stateONON
Key behaviourSnap to one stable stateUniversal logic gateControlled expression
Ideal sim duration24h24h48h

Week 7 HW: Genetic Circuits Part II

Intracellular Artificial Neural Networks

  1. What advantages do IANNs have over traditional genetic circuits, whose input/output behaviors are Boolean functions?
  • Traditional genetic circuits operate on Boolean logic (AND, OR, NOT), which digitizes biological signals into strict ON (1) or OFF (0) states. IANNs, which operate on analog logic, allows for
  1. Describe a useful application for an IANN; include a detailed description of input/output behavior, as well as any limitations an IANN might face to achieve your goal.

  2. Below is a diagram depicting an intracellular single-layer perceptron where the X1 input is DNA encoding for the Csy4 endoribonuclease and the X2 input is DNA encoding for a fluorescent protein output whose mRNA is regulated by Csy4. Tx: transcription; Tl: translation. Draw a diagram for an intracellular multilayer perceptron where layer 1 outputs an endoribonuclease that regulates a fluorescent protein output in layer 2.

inhibitor ──⊣┐
              ├──→ output        output = excitatory AND NOT(inhibitor)
excitatory ──→┘

Layer 2 is an INHIBIT gate: X3 is the excitatory input (fluorescent protein mRNA), RNase2 from Layer 1 is the inhibitory input, and fluorescence only appears when X3 is present and Layer 1 has successfully suppressed RNase2 via RNase1.

X1 ──⊣┐
       ├──→ RNase2 ──⊣┐
X2 ──→┘                ├──→ ● Fluorescence
               X3 ──→─┘

An intracellular two-layer perceptron in which Layer 1 produces an endoribonuclease that post-transcriptionally regulates the Layer 2 fluorescent protein output.

Fungal Materials

  1. What are some examples of existing fungal materials and what are they used for? What are their advantages and disadvantages over traditional counterparts?
  • Most existing fungal materials are made from Mycelium, used for biopackaging, fungal leather/textile. The advantage is sustainability, given the biomaterial, mycelium is 100% compostable, and make efficient use of resources. The down side is that it’s susceptible to moisture, and the nature of the living biomaterial made standardization harder.
  1. What might you want to genetically engineer fungi to do and why? What are the advantages of doing synthetic biology in fungi as opposed to bacteria?
  • Fungi could be useful in tackling environmental issue, such as engineered to absorb and sequester heavy metals and radioactive waste from contaminated soil.
  • Fungi is better than bacteria because it’s a fun guy! (not funny..)

Week 9 HW: Cell Free Systems

General homework questions

  1. Explain the main advantages of cell-free protein synthesis over traditional in vivo methods, specifically in terms of flexibility and control over experimental variables. Name at least two cases where cell-free expression is more beneficial than cell production.
  2. Describe the main components of a cell-free expression system and explain the role of each component.
  3. Why is energy provision regeneration critical in cell-free systems? Describe a method you could use to ensure continuous ATP supply in your cell-free experiment.
  4. Compare prokaryotic versus eukaryotic cell-free expression systems. Choose a protein to produce in each system and explain why.
  5. How would you design a cell-free experiment to optimize the expression of a membrane protein? Discuss the challenges and how you would address them in your setup.
  6. Imagine you observe a low yield of your target protein in a cell-free system. Describe three possible reasons for this and suggest a troubleshooting strategy for each.

Homework question from Kate Adamala

Design an example of a useful synthetic minimal cell as follows:

  1. Pick a function and describe it.
  • What would your synthetic cell do? What is the input and what is the output?
  • Would this function be realized by cell-free Tx/Tl alone, without encapsulation?
  • Could this function be realized by genetically modified natural cell?
  • Describe the desired outcome of your synthetic cell operation.
  1. Design all components that would need to be part of your synthetic cell.
  • What would be the membrane made of?
  • What would you encapsulate inside? Enzymes, small molecules.
  • Which organism your Tx/Tl system will come from? Is bacterial OK, or do you need a mammalian system for some reason? (hint: for example, if you want to use small molecule modulated promotors, like Tet-ON, you need mammalian)
  • How will your synthetic cell communicate with the environment? (hint: are substrates permeable? or do you need to express the membrane channel?)
  1. Experimental details
  • List all lipids and genes. (bonus: find the specific genes; for example, instead of just saying “small molecule membrane channel” pick the actual gene.)
  • How will you measure the function of your system?

Homework question from Peter Nguyen

  1. Freeze-dried cell-free systems can be incorporated into all kinds of materials as biological sensors or as inducible enzymes to modify the material itself or the surrounding environment. Choose one application field — Architecture, Textiles/Fashion, or Robotics — and propose an application using cell-free systems that are functionally integrated into the material. Answer each of these key questions for your proposal pitch:
  • Write a one-sentence summary pitch sentence describing your concept.
  • How will the idea work, in more detail? Write 3-4 sentences or more.
  • What societal challenge or market need will this address?
  • How do you envision addressing the limitation of cell-free reactions (e.g., activation with water, stability, one-time use)?

Homework question from Ally Huang

Freeze-dried cell-free reactions have great potential in space, where resources are constrained. As described in my talk, the Genes in Space competition challenges students to consider how biotechnology, including cell-free reactions, can be used to solve biological problems encountered in space. While the competition is limited to only high school students, your assignment will be to develop your own mock Genes in Space proposal to practice thinking about biotech applications in space!

For this particular assignment, your proposal is required to incorporate the BioBits® cell-free protein expression system, but you may also use the other tools in the Genes in Space toolkit (the miniPCR® thermal cycler and the P51 Molecular Fluorescence Viewer). For more inspiration, check out https://www.genesinspace.org/ .

  1. Provide background information that describes the space biology question or challenge you propose to address. Explain why this topic is significant for humanity, relevant for space exploration, and scientifically interesting. (Maximum 100 words)
  2. Name the molecular or genetic target that you propose to study. Examples of molecular targets include individual genes and proteins, DNA and RNA sequences, or broader -omics approaches. (Maximum 30 words)
  3. Describe how your molecular or genetic target relates to the space biology question or challenge your proposal addresses. (Maximum 100 words)
  4. Clearly state your hypothesis or research goal and explain the reasoning behind it. (Maximum 150 words)
  5. Outline your experimental plan - identify the sample(s) you will test in your experiment, including any necessary controls, the type of data or measurements that will be collected, etc. (Maximum 100 words)

Week 10 HW: Imaging and Measurement

Week 11 HW: Bioproduction and Cloud Labs

Part A: The 1,536 Pixel Artwork Canvas | Collective Artwork

This is a lovely piece of art created by HTGAA community, I love the bio elements and the niche reference to DNA yay.

I received the link but forgot to contribute. But that wasn’t intentional because maybe someday I will return as a TA for this course.

Although with my pathetic knowledge in bio I will probably get fired on the spot.

What I really liked about the project is the creative use of color palette and the layout of words, and also the fact that I was able to see the quantitative recollection of people’s contribution.

Part B: Cell-Free Protein Synthesis | Cell-Free Reagents

  1. Referencing the cell-free protein synthesis reaction composition (the middle box outlined in yellow on the image above, also listed below), provide a 1-2 sentence description of what each component’s role is in the cell-free reaction.

E. coli Lysate

ComponentRole
BL21(DE3) Star Lysate (with T7 RNA Polymerase)Provides the complete transcription and translation machinery — ribosomes, tRNAs, aminoacyl-tRNA synthetases, initiation/elongation factors, and chaperones. The DE3 genomic insertion encodes T7 RNA Polymerase, enabling high-efficiency transcription from T7 promoter-driven DNA templates.

Salts and Buffer

ComponentRole
Potassium GlutamatePrimary K⁺ source for ribosome function and osmotic balance; glutamate is a preferred counterion over Cl⁻, which is inhibitory to translation
HEPES-KOH pH 7.5Maintains physiological pH to stabilize enzymatic activity throughout the reaction
Magnesium GlutamateSupplies Mg²⁺, essential for ribosome assembly, RNA structural integrity, and phosphotransfer reactions
Potassium phosphate (monobasic/dibasic)Provides a phosphate buffer reserve and inorganic phosphate for nucleotide phosphorylation reactions

Energy and Nucleotide System

ComponentRole
GlucosePrimary carbon and energy source; feeds glycolysis to drive ATP regeneration and downstream metabolism
RiboseEnters the pentose phosphate pathway (PPP) to generate PRPP for nucleotide salvage and NADPH for redox balance
AMP, CMP, GMP, UMPNucleoside monophosphates (NMPs) serve as transcription precursors, phosphorylated in situ to NTPs by endogenous kinases
GuanineFree nucleobase salvaged via HGPRT to produce GMP, supplementing the GTP pool for transcription (see Bonus)

Translation Mix (Amino Acids)

ComponentRole
17 Amino Acid MixProvides the bulk substrates required for ribosomal translation and polypeptide elongation
TyrosineAdded separately due to its poor aqueous solubility at neutral pH; typically prepared as a pH 12 suspension
CysteineAdded separately due to oxidation sensitivity and reactivity; prone to disulfide formation in mixed stock solutions

Additives

ComponentRole
NicotinamideNAD⁺ precursor (vitamin B3) that sustains the redox cofactor pool required for glycolysis and energy metabolism; also inhibits NAD⁺-consuming enzymes (e.g., sirtuins, PARPs) that would otherwise deplete the pool

Backfill

ComponentRole
Nuclease-Free WaterBrings the reaction to final volume without introducing RNases that would degrade mRNA templates or tRNAs

  1. Describe the main differences between the 1-hour optimized PEP-NTP master mix and the 20-hour NMP-Ribose-Glucose master mix. (2-3 sentences)

The 1-hour PEP-NTP system supplies NTPs directly (ATP 1.5 mM, GTP 1.5 mM, CTP/UTP 875 µM each) alongside phosphoenolpyruvate (PEP-Mono, 17.5 mM) and Maltodextrin as fast-acting energy donors — this provides immediate substrates for transcription and translation but is short-lived because PEP is rapidly exhausted and accumulating inorganic phosphate (Pᵢ) inhibits the reaction.

The 20-hour NMP-Ribose-Glucose system instead supplies nucleoside monophosphates (AMP, CMP, UMP) and substitutes GMP entirely with free Guanine (200 µM), relying on endogenous cellular enzymes to phosphorylate NMPs to NTPs using metabolic energy regenerated from Ribose (77.4 mM) and Glucose (6.9 mM), avoiding rapid Pᵢ accumulation and sustains productive synthesis far longer. The PEP-NTP formulation also includes a richer additive cocktail (Spermidine, DMSO, cAMP, NAD, Folinic Acid) to maximize short-burst translation efficiency, whereas the NMP-Ribose system is simplified to Nicotinamide alone and compensates with higher amino acid concentrations (~4.1 mM vs. 2.5 mM) to support extended protein production.

  1. Bonus question: How can transcription occur if GMP is not included but Guanine is?

Guanine is converted to GMP via the purine salvage pathway:

Guanine + PRPP  →(HGPRT)→  GMP + PPi

PRPP (5-phosphoribosyl-1-pyrophosphate) is generated from ribose-5-phosphate, a product of the pentose phosphate pathway fed by ribose. The GMP produced is then sequentially phosphorylated by endogenous kinases:

GMP  →(Guanylate kinase)→  GDP  →(NDP kinase)→  GTP

GTP is the actual substrate incorporated by T7 RNAP during transcription. Using free Guanine rather than GMP is both cost-effective and avoids the chemical instability of pre-formed GTP in the reaction mix — the lysate’s endogenous HGPRT activity handles the conversion efficiently.