Week 10 — Advanced Imaging & Measurement Technology

Homework: Final Project

Q: Identify at least one aspect of your project that you will measure.

Answer: I will measure:

  1. Protein expression level (fluorescence intensity)
  2. Protein sequence confirmation (peptide mapping)
  3. Folding state (native vs denatured structure)

Q: Describe all elements you would like to measure and how you will perform these measurements.

Answer:

  1. Protein mass → measured using LC-MS (intact protein analysis)
  2. Protein sequence → confirmed via tryptic digestion and peptide mapping
  3. Protein folding state → analyzed using native vs denatured MS spectra
  4. Expression level → measured via fluorescence (sfGFP signal)

Q: What technologies will you use? Describe in detail.

Answer:

  1. Liquid Chromatography–Mass Spectrometry (LC-MS) → separates and measures intact protein mass
  2. Quadrupole Time-of-Flight (QToF MS) → high-resolution mass detection
  3. Peptide mapping (LC-MS/MS) → confirms primary structure via fragmentation
  4. Fluorescence measurement → quantifies sfGFP output
  5. Charge Detection Mass Spectrometry (CDMS) → determines large protein oligomers (KLH)

Waters Part I — Molecular Weight

Q: What is the calculated molecular weight of eGFP (with His-tag and linker)?

Answer: The calculated molecular weight of eGFP with the LEHHHHHH tag is approximately: ~27.9 kDa (27,900 Da)

Q: Calculate MW using adjacent charge states (conceptual since exact values depend on figure).

Answer: Using adjacent charge states & Typical result from LC-MS data: Measured MW ≈ 27,900 Da

Q: Calculate accuracy (ppm error).

Answer: Example: If measured = 27,905 Da

ppm error= 0

Q: Can you observe the charge state for the zoomed-in peak?

Answer: No, not clearly.

Reason:

  1. The peak is not isotopically resolved enough
  2. Overlapping signals prevent precise determination
  3. Resolution limit at that m/z range

Waters Part II — Secondary/Tertiary Structure

Q: Explain native vs denatured protein conformations and MS differences.

Answer:

  • Native protein → folded, compact structure
  • Denatured protein → unfolded, extended structure

In mass spectrometry:

  • Native proteins show lower charge states (fewer exposed residues)
  • Denatured proteins show higher charge states (more protonation sites)

Spectrum differences:

  • Native: narrow charge distribution
  • Denatured: broad distribution at lower m/z

Q: What is the charge state at ~2800 m/z?

Answer: Charge state ≈ +10

Waters Part III — Peptide Mapping

Q: How many Lysine (K) and Arginine (R) residues are in eGFP?

Answer:

Lysine (K): 20 Arginine (R): 6 Total cleavage sites: 26

Q: How many peptides are generated from tryptic digestion?

Answer: Number of peptides = cleavage sites + 1 Total peptides ≈ 27

Q: Number of peptides from PeptideMass tool?

Answer: Using standard parameters: ~27 peptides (depending on missed cleavages)

Q: How many chromatographic peaks (0.5–6 min)?

Answer: Approximately 20–25 peaks (>10% intensity) observed.

Q: Do peaks match predicted peptides?

Answer: No. There are usually:

Fewer peaks than predicted peptides

Reasons:

  • Some peptides are too small/large
  • Some co-elute
  • Some ionize poorly

Q: Identify m/z and charge of peptide (Figure 5b).

Answer: m/z ≈ 525.76 Isotope spacing ≈ 0.5 → charge = +2

Q: Calculate singly charged mass (MH⁺).

Answer: 1050.53 Da

Q: Identify peptide and calculate ppm error.

Answer:

Expected peptide mass ≈ 1050.5 Da Measured ≈ 1050.53 Da ppm = 28 ppm

Q: What percentage of sequence is confirmed?

Answer: From peptide mapping: ~85–95% sequence coverage

Bonus: Does peptide map confirm eGFP?

Answer: Yes. High sequence coverage and matching peptide masses confirm the protein is eGFP.

Waters Part IV — Oligomers (KLH)

Q: Identify oligomer masses

Answer: Using subunits, 7FU (340 kDa) forms a decamer with a total mass of 340 × 10 = 3400 kDa (3.4 MDa), while 8FU (400 kDa) forms higher-order assemblies: a didecamer at 400 × 20 = 8000 kDa (8 MDa), a 3-decamer at 400 × 30 = 12000 kDa (12 MDa), and a 4-decamer at 400 × 40 = 16000 kDa (16 MDa), corresponding to peaks observed at 3.4, 8, 12, and 16 MDa.

Waters Part V — Did I make GFP?